Programming Data Structure And Algorithms Using Python Assignment 4

                     

Course Name: Programming Data Structure And Algorithms Using Python

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These are the solutions of Programming Data Structure And Algorithms Using Python Assignment 4


Q1) Consider the following Python function.
def mystery (1):
if 1 == [] :
return (1)
else :
return(mystery (1[1 : ])+1[1])
What does mystery ([22, 14, 19, 65, 82,55]) return?

Answer: [55, 82, 65, 19, 14, 22]


Q2) What is the value of pairs after the following assignment?
pairs = [ (x,y) for x in range (4,1,-1) for y in range (5,1,-1) if (x+y)%3 ==0]

Answer: [(4,5), (4,2), (3,3), (2,4)]


These are the solutions of Programming Data Structure And Algorithms Using Python Assignment 4


Q3) Consider the following dictionary.
wickets = {“Tests” : {“Bumrah” : [3,5,2,3], “Shami” : [4,4,1,0], “Ashwin” : [2,1,7,4]}, “ODI” : {“Bumrah” : [2, 0], “Shami” : [1,2]}}
Which of the following statements does not generate an error?

wickets [“ODI”][“Ashwin”][ : ] = [4,4]
wickets [“ODI”][“Ashwin”].extend ([4,4])
wickets [“ODI”][“Ashwin”] = [4,4]
wickets [“ODI”][“Ashwin”] = wickets [“ODI”][“Ashwin”] + [4,4]

Answer: wickets [“ODI”][“Ashwin”] = [4,4]


Q4) Assume that hundreds has been initialized as an empty dictionary :
hundreds = {}
Which of the following generates an error?

hundreds [“Tendulkar, international”] = 100
hundreds [“Tendulkar”] = {“international” : 100}
hundreds [(“Tendulkar”, “international”)] = 100
hundreds [[“Tendulkar”, “international”]] = 100

Answer: hundreds [[“Tendulkar”, “international”]] = 100


These are the solutions of Programming Data Structure And Algorithms Using Python Assignment 4


Programming Assignment Solution

Q1. Write two Python functions as specified below. Paste the text for both functions together into the submission window. Your function will be called automatically with various inputs and should return values as specified. Do not write commands to read any input or print any output.

Solution:

def frequency(l):
    SET=set(l)
    LIST=list(SET)
    newl=list()
    for a in LIST:
        newl.append(l.count(a))
    mi=min(newl)
    ma=max(newl)
    mil=[]
    mal=[]
    for b in range(len(newl)):
        if newl[b]==mi:

             mil.append(LIST[b])
        if newl[b]==ma:
                    
             mal.append(LIST[b])
    mil.sort()
    mal.sort()
    return(mil,mal)								

 
def onehop(l):
    ans=list()
    l.sort()
    for x in range(len(l)):
         for y in range(len(l)):
            if l[x]!=l[y]:
                if l[x][1]==l[y][0]:
                    q=l[x][0]
                    w=l[y][1]
                    if q!=w:
                        t=[q,w]
                        t=tuple(t)
                        if t not in ans:
                            ans.append(tuple(t)) 
    ans.sort()          
    return (ans)

These are the solutions of Programming Data Structure And Algorithms Using Python Assignment 4

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These are the solutions of Programming Data Structure And Algorithms Using Python Assignment 4